Number System 5

Test of a Prime Number

A prime number is only divisible by 1 and by the number it self. The first prime number is 2. Every prime number other then 2 is odd, but every odd number is not necessarily a prime number. To test whether any given number is a prime number or not, following steps are to be considered:

Step 1:- Find an integer (x) which approximate square root is greater then of the given number.

Step 2:- Test the divisibility of the given number by every prime number less than x.

Step 3:- If the given number is divisible by any of them in Step 2, then the given number is not a prime number.

If the given number is not divisible by any of them in Step 2, then the given number is a prime number.

Ex.:- Consider a number 203. Test if it is a prime or not.

Step 1:- The approximate square root of 203 is 14 plus, take x = 15.

Step 2:- Check the divisibility of 203 by the prime number less than 15 i.e., by 2, 3, 5, 7, 11, 13.

Step 3:- 203 is divisible by 7. Thus, it is not a prime number


SUM rules on Natural Numbers

Rule 1

Sum of the first n natural numbers (Starting from 1) = n(n + 1)/2.

Ex.:- Sum of 1 to 74 = 74 x 75/2 = 2775


Rule 2

Sum of first n odd numbers (Starting from 1) = n2

Ex.:- Sum of first 7 odd numbers ( 1 + 3 + 5 + 7 + 9 + 11 + 13) = 72 = 49

Rule 3

Sum of first n even numbers (Starting from 1) = n(n + 1)

Ex.:- Sum of first 9 even numbers (2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18) = 9(9 + 1) = 90.


Rule 4

Sum of squares of first natural numbers (Starting from 1) = n(n + 1)(2n + 1)/6

Ex.:- Sum of squares of first 8 natural numbers

12 + 22 + 32 + 42 + 52 + 62 + 72 + 82 = 8(8 + 1)(2 x 8 + 1)/6

= 8 x 9 x 17/6 = 204


Rule 5

Sum of cubes of first n natural numbers = [ n(n + 1)/2 ]2

Ex.:- Sum of cubes of first 6 natural numbers = 13 + 23 + 33 + 43 + 53 + 63 = [ 6(6 + 1)/2 ]2 = 441


Note:- For applying Rule 2 and Rule 3, it is required to find how many odd numbers or even numbers are there in the given series.

In the first ‘n’ natural numbers,

If n is even, then there are n/2 odd numbers and n/2 even number

If n is odd, then there are n + ½ odd numbers and n – ½ even numbers


Ex.:- From 1 to 30, as 30 is even, there are 15 odd numbers and 15 even numbers.

From 1 to 29, as 29 is odd, there are 29 + ½ = 15 odd numbers and 29 – ½ even numbers.










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